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 <title><![CDATA[求教欧姆龙cp1h这步程序怎么理解？]]></title>
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 <description><![CDATA[Latest 50 replies of 求教欧姆龙cp1h这步程序怎么理解？]]></description>
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 <description><![CDATA[单个数字是通道，包含16各位

其实可以当成把一个数字传输给一个16个位组成的寄存器，这个寄存器16个位对应16个输出位]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-1653646#1989319.html]]></link>
 <author><![CDATA[nightblueblu]]></author>
 <category><![CDATA[欧姆龙工控论坛]]></category>
 <pubdate><![CDATA[Mon, 30 Jul 2018 02:15:09 +0000]]></pubdate>
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 <description><![CDATA[数据传送，&amp;1和CH7，你转成2进制就明白了，实际上是位的字形态传送]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-1653646#1989047.html]]></link>
 <author><![CDATA[fcq417]]></author>
 <category><![CDATA[欧姆龙工控论坛]]></category>
 <pubdate><![CDATA[Sat, 28 Jul 2018 02:47:25 +0000]]></pubdate>
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 <description><![CDATA[這簡單將常數１傳到CH7就是７、００ on
Mov ０ １００ 就是將100ch通道歸零嘍]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-1653646#1988998.html]]></link>
 <author><![CDATA[xiao_ming]]></author>
 <category><![CDATA[欧姆龙工控论坛]]></category>
 <pubdate><![CDATA[Fri, 27 Jul 2018 13:42:59 +0000]]></pubdate>
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