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 <title><![CDATA[用X轴和Y轴怎样画一个圆出来]]></title>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-1584318.html]]></link>
 <description><![CDATA[Latest 50 replies of 用X轴和Y轴怎样画一个圆出来]]></description>
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 <title><![CDATA[]]></title>
 <description><![CDATA[[quote]引用第8楼wu32u2于2017-05-25 17:24发表的&nbsp;&nbsp;:
[url]http://www.ymmfa.com/read-gktid-1536579.html[/url]
[/quote]


屏通的触摸屏，2坐标曲线图功果然很强大！ [s:21]&nbsp;&nbsp;[s:21]&nbsp;&nbsp;[s:21]]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-1584318#1892180.html]]></link>
 <author><![CDATA[愚公移山]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Fri, 26 May 2017 14:01:48 +0000]]></pubdate>
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<item>
 <title><![CDATA[]]></title>
 <description><![CDATA[[url]http://www.ymmfa.com/read-gktid-1536579.html[/url]]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-1584318#1891794.html]]></link>
 <author><![CDATA[wu32u2]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Thu, 25 May 2017 09:24:10 +0000]]></pubdate>
</item>
<item>
 <title><![CDATA[]]></title>
 <description><![CDATA[圆弧插补]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-1584318#1891430.html]]></link>
 <author><![CDATA[金额咖啡馆]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Wed, 24 May 2017 00:36:06 +0000]]></pubdate>
</item>
<item>
 <title><![CDATA[]]></title>
 <description><![CDATA[2楼的思路就是的]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-1584318#1891364.html]]></link>
 <author><![CDATA[焦刘吉]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Tue, 23 May 2017 12:26:45 +0000]]></pubdate>
</item>
<item>
 <title><![CDATA[]]></title>
 <description><![CDATA[对不起，上面写错了

x=rcosz
y=rsinz

z作为虚拟轴0-360度旋转]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-1584318#1891296.html]]></link>
 <author><![CDATA[daiz63]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Tue, 23 May 2017 07:48:16 +0000]]></pubdate>
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<item>
 <title><![CDATA[]]></title>
 <description><![CDATA[x=rsinz
y=rsinz

z作为虚拟轴0-360度旋转]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-1584318#1891290.html]]></link>
 <author><![CDATA[daiz63]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Tue, 23 May 2017 07:03:18 +0000]]></pubdate>
</item>
<item>
 <title><![CDATA[]]></title>
 <description><![CDATA[插补指令]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-1584318#1890774.html]]></link>
 <author><![CDATA[hanqin]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Sun, 21 May 2017 00:42:03 +0000]]></pubdate>
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<item>
 <title><![CDATA[]]></title>
 <description><![CDATA[X^2+Y^2=R^2
先置位（0，R），然后让X在0→R→0→-R→0之间以最小分辨率移动，那么Y=根号R^2-X^2,当X到最大然后转回到0时，Y取计算值的负值画另半圆。
当然这些是俺在C++中画圆时用的方法。不清楚你的要求是否能达到。]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-1584318#1890754.html]]></link>
 <author><![CDATA[静夜思飘]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Sat, 20 May 2017 13:48:23 +0000]]></pubdate>
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<item>
 <title><![CDATA[]]></title>
 <description><![CDATA[算了吧！交由軸卡自己演算吧。除非你想自己算出來。]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-1584318#1890748.html]]></link>
 <author><![CDATA[xiao_ming]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Sat, 20 May 2017 13:18:08 +0000]]></pubdate>
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