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 <title><![CDATA[求助]]></title>
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 <description><![CDATA[二楼说的应该是对的，可以试下]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-1513260#1669310.html]]></link>
 <author><![CDATA[lan333000]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Fri, 22 May 2015 00:47:15 +0000]]></pubdate>
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 <description><![CDATA[分度圆，两个齿轮圆周比是14：27，那么假设大圆一周是L， 小圆应该走同样线长。 为 27/14*L
大圆走一半，小圆走27/14*4000/2个脉冲。]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-1513260#1669177.html]]></link>
 <author><![CDATA[flyfeky]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Thu, 21 May 2015 10:36:52 +0000]]></pubdate>
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 <description><![CDATA[好的谢谢]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-1513260#1669172.html]]></link>
 <author><![CDATA[萝卜君]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Thu, 21 May 2015 10:14:04 +0000]]></pubdate>
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 <title><![CDATA[]]></title>
 <description><![CDATA[[[27/2]/14]*4000=3857.1428
不能整除會有累積誤差，如有精度要求一定動作次數後記得歸一次原點。[s:21]]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-1513260#1669113.html]]></link>
 <author><![CDATA[东华数字]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Thu, 21 May 2015 07:09:49 +0000]]></pubdate>
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 <title><![CDATA[]]></title>
 <description><![CDATA[(27/14-1)*4000&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; 好像是的 [s:28] 



呵呵&nbsp;&nbsp; 不太懂&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;你是用什么控制的？&nbsp;&nbsp;[s:28]]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-1513260#1669098.html]]></link>
 <author><![CDATA[a996185055]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Thu, 21 May 2015 06:48:56 +0000]]></pubdate>
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