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 <title><![CDATA[4-20mA模拟量对应0-2000的直线方程关系]]></title>
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 <description><![CDATA[Latest 50 replies of 4-20mA模拟量对应0-2000的直线方程关系]]></description>
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<item>
 <title><![CDATA[]]></title>
 <description><![CDATA[y=4+0.2x
z=25x
z=125*（y-4）
x是0-80的值&nbsp;&nbsp;y是4-20的值&nbsp;&nbsp;z是0-2000的值
本人初学者&nbsp;&nbsp;随便说说&nbsp;&nbsp;别当真]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-1427918#1445127.html]]></link>
 <author><![CDATA[903636024]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Mon, 20 May 2013 08:16:43 +0000]]></pubdate>
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 <title><![CDATA[]]></title>
 <description><![CDATA[初中方程式：Y=(A/B)*X+C,A/B是斜率，C是当X=0时对应的Y的值。]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-1427918#1445111.html]]></link>
 <author><![CDATA[wu32u2]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Mon, 20 May 2013 07:38:43 +0000]]></pubdate>
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 <title><![CDATA[]]></title>
 <description><![CDATA[[quote]引用第2楼john42tw于2013-05-16 08:13发表的&nbsp;&nbsp;:
(20-4)/(80-0)=16/80=0.2

0==&gt;0*0.2+4=4mA
10=&gt;10*0.2+4=6mA
15=&gt;15*02.+4=7mA
.......
[/quote]
 

数字量怎么求呢？？？]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-1427918#1444926.html]]></link>
 <author><![CDATA[wanzhen2006]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Mon, 20 May 2013 00:36:42 +0000]]></pubdate>
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 <title><![CDATA[]]></title>
 <description><![CDATA[看看 [s:21]&nbsp;&nbsp;[s:28]&nbsp;&nbsp;[s:28]]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-1427918#1443472.html]]></link>
 <author><![CDATA[602424236]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Thu, 16 May 2013 03:12:45 +0000]]></pubdate>
</item>
<item>
 <title><![CDATA[]]></title>
 <description><![CDATA[(20-4)/(80-0)=16/80=0.2

0==&gt;0*0.2+4=4mA
10=&gt;10*0.2+4=6mA
15=&gt;15*02.+4=7mA
80=&gt;80*0.2+4=20mA]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-1427918#1443376.html]]></link>
 <author><![CDATA[john42tw]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Thu, 16 May 2013 00:13:46 +0000]]></pubdate>
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 <title><![CDATA[]]></title>
 <description><![CDATA[10对应的是30
15对应的是55
D=(A-A0)X(DM-D0)/(AM-A0)+D0
D=要求的值
AM=模拟量最大值
A0=模拟量最小值
DM=工程量最大值
D0=工程量最小值
西门子有FC105、FC106功能， 欧姆龙有SCL指令的。]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-1427918#1443348.html]]></link>
 <author><![CDATA[hanqin]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Wed, 15 May 2013 22:08:38 +0000]]></pubdate>
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