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 <title><![CDATA[脉冲计算]]></title>
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 <description><![CDATA[[quote]引用第1楼mww163.com于2013-01-05 12:33发表的&nbsp;&nbsp;:
360/电机角度1.8=200脉冲
16/200=0.08mm 就是一个脉冲走过的距离
[/quote]


正解，不过注意，一般都是细分的，比如细分到0.9°]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-1417745#1398234.html]]></link>
 <author><![CDATA[catfree]]></author>
 <category><![CDATA[三菱工控论坛]]></category>
 <pubdate><![CDATA[Sat, 05 Jan 2013 04:45:09 +0000]]></pubdate>
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 <description><![CDATA[360/电机角度1.8=200脉冲
16/200=0.08mm 就是一个脉冲走过的距离]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-1417745#1398230.html]]></link>
 <author><![CDATA[mww163.com]]></author>
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 <pubdate><![CDATA[Sat, 05 Jan 2013 04:33:25 +0000]]></pubdate>
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