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 <title><![CDATA[用程序准确的表达1PG的地址；]]></title>
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 <description><![CDATA[Latest 50 replies of 用程序准确的表达1PG的地址；]]></description>
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 <description><![CDATA[问题已经解决&nbsp;&nbsp;&nbsp;&nbsp;谢谢]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-1407907#1372538.html]]></link>
 <author><![CDATA[512998120]]></author>
 <category><![CDATA[程序样例]]></category>
 <pubdate><![CDATA[Tue, 06 Nov 2012 01:41:09 +0000]]></pubdate>
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 <title><![CDATA[]]></title>
 <description><![CDATA[有没有控制速度和位置的程序例子~~~~~简单易懂的~~~~~~~谢谢]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-1407907#1361864.html]]></link>
 <author><![CDATA[512998120]]></author>
 <category><![CDATA[程序样例]]></category>
 <pubdate><![CDATA[Sat, 20 Oct 2012 01:41:32 +0000]]></pubdate>
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 <title><![CDATA[]]></title>
 <description><![CDATA[（JOG+指令
B4=1&nbsp;&nbsp;而时间为达到300MS 发送一个正转脉冲
B4=1&nbsp;&nbsp;且时间超过300MS 以连续送出正转脉冲）&nbsp;&nbsp; 怎么理解呢&nbsp;&nbsp;]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-1407907#1361851.html]]></link>
 <author><![CDATA[512998120]]></author>
 <category><![CDATA[程序样例]]></category>
 <pubdate><![CDATA[Sat, 20 Oct 2012 01:15:48 +0000]]></pubdate>
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<item>
 <title><![CDATA[]]></title>
 <description><![CDATA[#3的b9表示旋转方向：即ｂ９＝０发送ＦＰ脉冲式增加方向；ｂ９＝１发送ＦＰ脉冲递减方向。
楼主是不是想实现正反转，＃２５的b4、b5分别表示JOG+和JOG-操作！]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-1407907#1361826.html]]></link>
 <author><![CDATA[jhbob]]></author>
 <category><![CDATA[程序样例]]></category>
 <pubdate><![CDATA[Sat, 20 Oct 2012 00:11:47 +0000]]></pubdate>
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