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 <title><![CDATA[编码器问题请教]]></title>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-1402892.html]]></link>
 <description><![CDATA[Latest 50 replies of 编码器问题请教]]></description>
 <copyright><![CDATA[Copyright(C) 工控人家园]]></copyright>
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 <description><![CDATA[谢谢！现在有点明也有点糊涂]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-1402892#1348479.html]]></link>
 <author><![CDATA[向日葵]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Fri, 21 Sep 2012 13:56:40 +0000]]></pubdate>
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 <title><![CDATA[]]></title>
 <description><![CDATA[刚没看见 I0.4 I0.6，是4个输入点，，程序里面需要通过编码器取得互不干扰的数据，有输入点是测角度的，有测速度，还有计数，复位输入等。]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-1402892#1348366.html]]></link>
 <author><![CDATA[绝世精灵]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Fri, 21 Sep 2012 09:24:13 +0000]]></pubdate>
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 <title><![CDATA[]]></title>
 <description><![CDATA[作用是什么啊！另外I0.4和I0.6是电源吗？还真没见过从输入口取电源！]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-1402892#1348297.html]]></link>
 <author><![CDATA[向日葵]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Fri, 21 Sep 2012 08:18:04 +0000]]></pubdate>
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 <title><![CDATA[]]></title>
 <description><![CDATA[图上只用两个输入点，0.1 、1.2。另两根是电源线]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-1402892#1348283.html]]></link>
 <author><![CDATA[绝世精灵]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Fri, 21 Sep 2012 07:44:02 +0000]]></pubdate>
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