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 <title><![CDATA[求解]]></title>
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 <description><![CDATA[[s:21] 感谢4楼的朋友&nbsp;&nbsp; 问题解决了]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-136657#1207468.html]]></link>
 <author><![CDATA[wxz11]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Fri, 10 Feb 2012 14:54:45 +0000]]></pubdate>
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 <description><![CDATA[公式我支持4楼的。]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-136657#1206972.html]]></link>
 <author><![CDATA[hanqin]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Fri, 10 Feb 2012 02:11:07 +0000]]></pubdate>
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 <description><![CDATA[19292]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-136657#1206971.html]]></link>
 <author><![CDATA[hanqin]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Fri, 10 Feb 2012 02:08:08 +0000]]></pubdate>
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 <title><![CDATA[]]></title>
 <description><![CDATA[假设 1400周长的直径为D1 ; 635Z周长的直径为D2;&nbsp;&nbsp; 1250周长的直径为D3 ; 材料的厚度为T;

则&nbsp;&nbsp;T*N= (D1-D2)


&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; 1400-635&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nb ..]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-136657#1206960.html]]></link>
 <author><![CDATA[bosshyup]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Fri, 10 Feb 2012 01:42:01 +0000]]></pubdate>
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 <title><![CDATA[]]></title>
 <description><![CDATA[[quote]引用第2楼wxz11于2012-02-10 04:12发表的&nbsp;&nbsp;:
楼上的是怎么解出来的&#160;&#160; 给个计算公式 [s:21]
[/quote]

圈数与周长的线性比。

24000/X=1400/1250

[s:39]]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-136657#1206941.html]]></link>
 <author><![CDATA[cvlsam]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Fri, 10 Feb 2012 01:10:34 +0000]]></pubdate>
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 <title><![CDATA[]]></title>
 <description><![CDATA[楼上的是怎么解出来的&nbsp;&nbsp; 给个计算公式 [s:21]]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-136657#1206898.html]]></link>
 <author><![CDATA[wxz11]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Thu, 09 Feb 2012 20:12:16 +0000]]></pubdate>
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 <description><![CDATA[21428,57]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-136657#1206863.html]]></link>
 <author><![CDATA[sylgq]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Thu, 09 Feb 2012 15:20:08 +0000]]></pubdate>
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