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 <title><![CDATA[帮我解释下就两步的程序]]></title>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-115854.html]]></link>
 <description><![CDATA[Latest 50 replies of 帮我解释下就两步的程序]]></description>
 <copyright><![CDATA[Copyright(C) 工控人家园]]></copyright>
 <generator><![CDATA[www.ymmfa.com]]></generator>
 <lastBuildDate><![CDATA[Thu, 16 Apr 2026 03:09:46 +0000]]></lastBuildDate>
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 <title><![CDATA[工控人家园]]></title>
 <link><![CDATA[http://www.ymmfa.com]]></link>
 <description><![CDATA[工控人家园]]></description>
  </image>
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 <title><![CDATA[]]></title>
 <description><![CDATA[用单脉冲指令实现]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-115854#1128650.html]]></link>
 <author><![CDATA[wuliang211]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Tue, 20 Sep 2011 07:37:02 +0000]]></pubdate>
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 <title><![CDATA[]]></title>
 <description><![CDATA[设计的问题，]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-115854#1128649.html]]></link>
 <author><![CDATA[wuliang211]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Tue, 20 Sep 2011 07:35:24 +0000]]></pubdate>
</item>
<item>
 <title><![CDATA[]]></title>
 <description><![CDATA[学习了!]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-115854#1128605.html]]></link>
 <author><![CDATA[wwx001]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Tue, 20 Sep 2011 06:23:58 +0000]]></pubdate>
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 <title><![CDATA[]]></title>
 <description><![CDATA[Q0.1有两条支路了，只要其中任何一条条件满足就能接通！]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-115854#1126496.html]]></link>
 <author><![CDATA[leijun1234]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Fri, 16 Sep 2011 07:10:22 +0000]]></pubdate>
</item>
<item>
 <title><![CDATA[原来西门子语句和其它不一样]]></title>
 <description><![CDATA[原以为AN是“与”，看了手册，才知道A是“与”，AN是“与非”。所以语句和梯形图是一致的。
程序是应该自保。]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-115854#1126445.html]]></link>
 <author><![CDATA[znz43]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Fri, 16 Sep 2011 05:42:38 +0000]]></pubdate>
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 <title><![CDATA[]]></title>
 <description><![CDATA[正如18楼所言，这个程序是钻了扫描周期的空子，输入触点可以立即动作，但输出线圈要到下一个扫描周期才会动作所以会一直有输出]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-115854#1126294.html]]></link>
 <author><![CDATA[ysheng9099]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Fri, 16 Sep 2011 00:34:20 +0000]]></pubdate>
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 <title><![CDATA[]]></title>
 <description><![CDATA[18楼的解释好像是对的&nbsp;&nbsp;谁来验证下]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-115854#1126091.html]]></link>
 <author><![CDATA[474419784]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Thu, 15 Sep 2011 12:37:54 +0000]]></pubdate>
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 <title><![CDATA[]]></title>
 <description><![CDATA[楼主的程序和二楼的梯型图不一致。AND 后的i0.4在语句中是常开，在梯型图中是常闭。
所以梯型图自保后不会断开。按楼主的语句不会生成二楼的梯型图，也不会自保。]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-115854#1125912.html]]></link>
 <author><![CDATA[znz43]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Thu, 15 Sep 2011 07:34:11 +0000]]></pubdate>
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 <title><![CDATA[]]></title>
 <description><![CDATA[明白不，这个很简单理解吧]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-115854#1125891.html]]></link>
 <author><![CDATA[wuliang211]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Thu, 15 Sep 2011 06:59:40 +0000]]></pubdate>
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 <title><![CDATA[]]></title>
 <description><![CDATA[把M1。0 的相关程序删除，Q0。1就会断开了]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-115854#1125876.html]]></link>
 <author><![CDATA[ysheng9099]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Thu, 15 Sep 2011 06:26:19 +0000]]></pubdate>
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 <title><![CDATA[]]></title>
 <description><![CDATA[这就是PLC逐行扫描的特点]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-115854#1125875.html]]></link>
 <author><![CDATA[ysheng9099]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Thu, 15 Sep 2011 06:24:24 +0000]]></pubdate>
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 <title><![CDATA[]]></title>
 <description><![CDATA[安先上后下先左后右扫描方式是可以按下通在按下断，运用中可以吗？]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-115854#1125503.html]]></link>
 <author><![CDATA[烟来如此]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Wed, 14 Sep 2011 14:02:03 +0000]]></pubdate>
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 <title><![CDATA[]]></title>
 <description><![CDATA[是不是想搞单键开关吖]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-115854#1125401.html]]></link>
 <author><![CDATA[omd]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Wed, 14 Sep 2011 11:56:56 +0000]]></pubdate>
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 <title><![CDATA[]]></title>
 <description><![CDATA[这个是西门子的吧]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-115854#1105009.html]]></link>
 <author><![CDATA[wlp2009]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Sun, 07 Aug 2011 14:35:10 +0000]]></pubdate>
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 <title><![CDATA[]]></title>
 <description><![CDATA[当断开I0.4的常闭触点后，Q0.1还会得电，要等到下一个扫描周期，才会断开]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-115854#1104891.html]]></link>
 <author><![CDATA[sug]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Sun, 07 Aug 2011 11:28:12 +0000]]></pubdate>
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 <title><![CDATA[]]></title>
 <description><![CDATA[[s:26]]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-115854#1104878.html]]></link>
 <author><![CDATA[东莞工控]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Sun, 07 Aug 2011 11:05:54 +0000]]></pubdate>
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 <title><![CDATA[]]></title>
 <description><![CDATA[&nbsp;&nbsp;&nbsp;&nbsp; 按2楼图，接通I0.4，M1.0、Q0.1接通；断开I0.4，第1个扫描周期时，这时的M1.0仍是接通的，又I0.4的常闭点接通，故M1.0保持接通，Q0.1还是接通。]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-115854#1104612.html]]></link>
 <author><![CDATA[qlin]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Sun, 07 Aug 2011 00:14:39 +0000]]></pubdate>
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 <title><![CDATA[]]></title>
 <description><![CDATA[二楼大哥写的样啊&nbsp;&nbsp;没什么区别啊&nbsp;&nbsp; 我还是不知道什么原因&nbsp;&nbsp;plc不是分时扫描 集中输出吗&nbsp;&nbsp;这样分析应该会断开啊]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-115854#1104478.html]]></link>
 <author><![CDATA[474419784]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Sat, 06 Aug 2011 12:30:56 +0000]]></pubdate>
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 <title><![CDATA[]]></title>
 <description><![CDATA[仔细看过一样呀。应该还是不能断开输出，自保了。]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-115854#1103947.html]]></link>
 <author><![CDATA[xf_lyj]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Fri, 05 Aug 2011 12:42:37 +0000]]></pubdate>
</item>
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 <title><![CDATA[]]></title>
 <description><![CDATA[不对哦&nbsp;&nbsp; 程序&nbsp;&nbsp;]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-115854#1103929.html]]></link>
 <author><![CDATA[5440205]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Fri, 05 Aug 2011 12:18:53 +0000]]></pubdate>
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 <title><![CDATA[]]></title>
 <description><![CDATA[2楼得很清楚]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-115854#1103886.html]]></link>
 <author><![CDATA[王风]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Fri, 05 Aug 2011 11:01:12 +0000]]></pubdate>
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 <title><![CDATA[]]></title>
 <description><![CDATA[plc扫描先上后下，先左后右]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-115854#1103584.html]]></link>
 <author><![CDATA[冰糖]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Fri, 05 Aug 2011 02:02:46 +0000]]></pubdate>
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 <title><![CDATA[]]></title>
 <description><![CDATA[仔细看程序，]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-115854#1103519.html]]></link>
 <author><![CDATA[汇荣铝业]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Fri, 05 Aug 2011 01:06:48 +0000]]></pubdate>
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 <title><![CDATA[]]></title>
 <description><![CDATA[跟扫描周期有关]]></description>
 <link><![CDATA[http://www.ymmfa.com/read-gktid-115854#1103513.html]]></link>
 <author><![CDATA[舒中胜]]></author>
 <category><![CDATA[综合讨论]]></category>
 <pubdate><![CDATA[Fri, 05 Aug 2011 00:58:23 +0000]]></pubdate>
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